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Tardigrade
Question
Mathematics
The relation f and g are defined by f(x)= begincasesx2, 0 ≤ x ≤ 3 3 x, 3 ≤ x ≤ 10 endcases and g(x)= begincasesx2, 0 ≤ x ≤ 2 3 x, 2 ≤ x ≤ 10 endcases, then
Q. The relation
f
and
g
are defined by
f
(
x
)
=
{
x
2
,
3
x
,
0
≤
x
≤
3
3
≤
x
≤
10
and
g
(
x
)
=
{
x
2
,
3
x
,
0
≤
x
≤
2
2
≤
x
≤
10
, then
71
169
Relations and Functions
Report Error
A
f
is a function
B
g
is a function
C
Both (a) and (b)
D
None of the above
Solution:
We have,
f
(
x
)
=
{
x
2
,
0
≤
x
≤
3
3
x
,
3
≤
x
≤
10
Since, every element has unique image by
f
. So,
f
is a function.
Now,
g
(
x
)
=
{
x
2
,
0
≤
x
≤
2
3
x
,
2
≤
x
≤
10
Since,
g
(
2
)
=
2
2
=
4
and
g
(
2
)
=
3
(
2
)
=
6
.
2 has two images. So,
g
is not a function.