The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be angles of minimum deviation for red and blue light respectively in a prism of this glass, then,:

Question

The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be angles of minimum deviation for red and blue light respectively in a prism of this glass, then,: (A)  D1 < D2 (B)  D1=D2 (C)  D1 can be less than or greater than D2 depending upon the angle of prism (D)  D1 >D2

Tardigrade Admin · Accepted Answer

D=(μ-1)A For blue light μ is greater than that for red light, so D2 >D1⋅

Q. The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let $D_{1}$ and $D_{2}$ be angles of minimum deviation for red and blue light respectively in a prism of this glass, then,:

$D_{1} < D_{2}$

$D_{1} = D_{2}$

$D_{1}$ can be less than or greater than $D_{2}$ depending upon the angle of prism

$D_{1} > D_{2}$

$D = (μ - 1) A$
For blue light $μ$ is greater than that for red light,
$so D_{2} > D_{1} \cdot$

Q. The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1​ and D2​ be angles of minimum deviation for red and blue light respectively in a prism of this glass, then,:

D1​<D2​

D1​=D2​

D1​ can be less than or greater than D2​ depending upon the angle of prism

D1​>D2​