The reducing character ( M 2+. species) in dihalides decreases as:

Question

The reducing character ( M 2+. species) in dihalides decreases as: (A) GeCl 2< SnCl 2< PbCl 2 (B) PbCl 2> GeCl 2> SnCl 2 (C) SnCl 2> PCl 2> GeCl 2 (D) GeCl 2> SnCl 2> PbCl 2

Tardigrade Admin · Accepted Answer

Due to inert pair effect the reducing character ( M 2+. species) in dihalides decrease in order:- GeCl 2> SnCl 2> PbCl 2

Q. The reducing character $(M^{2 +}$ species) in dihalides decreases as:

$G e C l_{2} < S n C l_{2} < P b C l_{2}$

$P b C l_{2} > G e C l_{2} > S n C l_{2}$

$S n C l_{2} > PC l_{2} > G e C l_{2}$

$G e C l_{2} > S n C l_{2} > P b C l_{2}$

Due to inert pair effect the reducing character $(M^{2 +} .$ species) in dihalides decrease in order:-

$G e C l_{2} > S n C l_{2} > P b C l_{2}$

Q. The reducing character (M2+ species) in dihalides decreases as:

GeCl2​<SnCl2​<PbCl2​

PbCl2​>GeCl2​>SnCl2​

SnCl2​>PCl2​>GeCl2​

GeCl2​>SnCl2​>PbCl2​