The real roots of the equation 2 x3-19 x2+57 x+k=0 are the first three terms of a geometric progression. If the geometric progression is increasing then the sum of its first n terms equals

Question

The real roots of the equation 2 x3-19 x2+57 x+k=0 are the first three terms of a geometric progression. If the geometric progression is increasing then the sum of its first n terms equals (A) ((3/2)) n -1 (B) 6(((3/2))n-1) (C) 4(2n-1) (D) 4(((3/2)) n -1)

Tardigrade Admin · Accepted Answer

Correct answer is (d) 4(((3/2)) n -1)

Q. The real roots of the equation $2 x^{3} - 19 x^{2} + 57 x + k = 0$ are the first three terms of a geometric progression.
If the geometric progression is increasing then the sum of its first $n$ terms equals

$(\frac{3}{2})^{n} - 1$

$6 ((\frac{3}{2})^{n} - 1)$

$4 (2^{n} - 1)$

$4 ((\frac{3}{2})^{n} - 1)$

Correct answer is (d) $4 ((\frac{3}{2})^{n} - 1)$

Q. The real roots of the equation 2x3−19x2+57x+k=0 are the first three terms of a geometric progression. If the geometric progression is increasing then the sum of its first n terms equals

(23​)n−1

6((23​)n−1)

4(2n−1)

4((23​)n−1)