The reaction X arrow Y is an exothermic reaction. Activation energy of the reaction for X into Y is 150 kJ mol-1. Enthalpy of reaction is 135 kJ mol-1. The activation energy for the reverse reaction, Y arrow X will be:

Question

The reaction X arrow Y is an exothermic reaction. Activation energy of the reaction for X into Y is 150 kJ mol-1. Enthalpy of reaction is 135 kJ mol-1. The activation energy for the reverse reaction, Y arrow X will be: (A) 280 kJ mol-1 (B) 285 kJ mol-1 (C) 270 kJ mol-1 (D) 15 kJ mol-1

Tardigrade Admin · Accepted Answer

X arrow Y; Δ H=-135 kJ/mol, Ea=150 kJ/mol For an exothermic reaction Ea(F.R.)=Δ H+E'a(B.R.) 150=-135+E'a(B.R.) E'a(B.R.)=258 kJ/mol,

Q. The reaction $X \to Y$ is an exothermic reaction. Activation energy of the reaction for $X$ into $Y$ is $150 k J m o l^{- 1}$ . Enthalpy of reaction is $135 k J m o l^{- 1}$ . The activation energy for the reverse reaction, $Y \to X$ will be:

$280 k J m o l^{- 1}$

$285 k J m o l^{- 1}$

$270 k J m o l^{- 1}$

$15 k J m o l^{- 1}$

$X \to Y; Δ H = - 135 k J / m o l,$
$E_{a} = 150 k J / m o l$
For an exothermic reaction
$E_{a (F . R .)} = Δ H + E_{a (B . R .)}^{'}$
$150 = - 135 + E_{a (B . R .)}^{'}$
$E_{a (B . R .)}^{'} = 258 k J / m o l,$

Q. The reaction X→Y is an exothermic reaction. Activation energy of the reaction for X into Y is 150kJmol−1. Enthalpy of reaction is 135kJmol−1. The activation energy for the reverse reaction, Y→X will be:

280kJmol−1

285kJmol−1

270kJmol−1

15kJmol−1