The reaction N2O5(in CCl4 solution)→2NO2(solution)+(1/2)O2(g) is of first order in N2O5 with rate constant 6.2 × 10-1 s-1 What is the value of rate of reaction when [N2O5]=1.25 mole?

Question

The reaction N2O5(in CCl4 solution)→2NO2(solution)+(1/2)O2(g) is of first order in N2O5 with rate constant 6.2 × 10-1 s-1 What is the value of rate of reaction when [N2O5]=1.25 mole? (A) 7.75 × 10-1 mole-1s-1 (B) 6.35 × 10-3 mole-1s-1 (C) 5.15× 10-5 mole-1s-1 (D) 3.85 × 10-1 mole-1s-1

Tardigrade Admin · Accepted Answer

Rate=K(N2O5)=6.2×10-1×1.25 =7.75×10-1 mol-1s-1

Q. The reaction
$N_{2} O_{5} (in CC l_{4} so l u t i o n) \to 2 N O_{2} (so l u t i o n) + \frac{1}{2} O_{2} (g)$ is
of first order in $N_{2} O_{5}$ with rate constant $6.2 \times 1 0^{- 1} s^{- 1}$ What is the value of rate of reaction when $[N_{2} O_{5}] = 1.25$ mole?

$7.75 \times 1 0^{- 1} m o l e^{- 1} s^{- 1}$

$6.35 \times 1 0^{- 3} m o l e^{- 1} s^{- 1}$

$5.15 \times 1 0^{- 5} m o l e^{- 1} s^{- 1}$

$3.85 \times 10 - 1 m o l e^{- 1} s^{- 1}$

$R a t e = K (N_{2} O_{5}) = 6.2 \times 1 0^{- 1} \times 1.25$
$= 7.75 \times 1 0^{- 1} m o l^{- 1} s^{- 1}$

Q. The reaction N2​O5​(inCCl4​solution)→2NO2​(solution)+21​O2​(g) is of first order in N2​O5​ with rate constant 6.2×10−1s−1 What is the value of rate of reaction when [N2​O5​]=1.25 mole?

7.75×10−1mole−1s−1

6.35×10−3mole−1s−1

5.15×10−5mole−1s−1

3.85×10−1mole−1s−1