Question

The ratio of minimum wavelengths of Lyman and Balmer series will be

• A. 1.25
• B. 0.25
• C. 5
• D. 10

Answer 1

Answer: (B)

For minimum wavelength,
$\lambda \propto n^2$
$\therefore \frac{{\lambda }_{\text{Lyman }}}{{\lambda }_{\text{Balmer }}}={\left(\frac{1}{2}\right)}^2$
$\frac{{\lambda }_L}{{\lambda }_B}=\frac{1}{4}=0.25$