The ratio of forward biased to reverse biased resistance for p-n junction diode is

Question

The ratio of forward biased to reverse biased resistance for p-n junction diode is (A)  10-1:1  (B)  10-2:1  (C)  10-3:1  (D)  10-4:1

Tardigrade Admin · Accepted Answer

Appears resistance ofp-n junction in forward biased Rf=102Ω . Appears resistance ofp-n junction in reverse bias Rr-106Ω (Rf/Rr)=(102/106)=10-4 Rf:Rr=10-4:1

Q. The ratio of forward biased to reverse biased resistance for p-n junction diode is

$10^{- 1} : 1$

$10^{- 2} : 1$

$10^{- 3} : 1$

$10^{- 4} : 1$

Appears resistance ofp-n junction in forward biased $R_{f} = 10^{2} Ω.$ Appears resistance ofp-n junction in reverse bias $R_{r} - 10^{6} Ω$ $\frac{R _{f}}{R _{r}} = \frac{10 ^{2}}{10 ^{6}} = 10^{- 4}$ $R_{f} : R_{r} = 10^{- 4} : 1$

Q. The ratio of forward biased to reverse biased resistance for p-n junction diode is

10−1:1

10−2:1

10−3:1

10−4:1

Appears resistance ofp-n junction in forward biased Rf​=102Ω. Appears resistance ofp-n junction in reverse bias Rr​−106Ω Rr​Rf​​=106102​=10−4 Rf​:Rr​=10−4:1

$10^{- 1} : 1$

$10^{- 2} : 1$

$10^{- 3} : 1$

$10^{- 4} : 1$

Appears resistance ofp-n junction in forward biased $R_{f} = 10^{2} Ω.$ Appears resistance ofp-n junction in reverse bias $R_{r} - 10^{6} Ω$ $\frac{R _{f}}{R _{r}} = \frac{10 ^{2}}{10 ^{6}} = 10^{- 4}$ $R_{f} : R_{r} = 10^{- 4} : 1$