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Tardigrade
Question
Chemistry
The ratio of area covered by second orbital to the first orbital is :
Q. The ratio of area covered by second orbital to the first orbital is :
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214
AFMC
AFMC 2004
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A
1 : 2
B
1 : 16
C
8 : 1
D
16 : 1
Solution:
According to Bohr
r
n
∝
Z
n
2
[
r
=
Z
0.529
n
2
A
˚
]
r
1
r
2
=
(
1
)
2
(
2
)
2
=
1
4
Area
=
π
r
2
⇒
A
1
A
2
=
π
r
1
2
π
r
2
2
=
(
r
1
r
2
)
2
=
(
1
4
)
2
=
1
16