Question

The rate of a certain biochemical reaction at physiological temperature (T) occurs $10^6$ times faster with enzyme than without. The change in the activation energy upon adding enzyme is :

• A. -6RT
• B. -6(2.303)RT
• C. +6RT
• D. +6(2.303)RT

Answer 1

Answer: (B)

$K=A{e}^{\frac{-E_a}{RT}}$
$K^{\prime }=A{e}^{\frac{-E_a}{RT}}=10^{6}K$
$A{e}^{\frac{-E_a}{RT}}=10^6\times A{e}^{\frac{-E_a}{RT}}$
$\frac{-E_a^{\prime }}{RT}=\frac{-E_a}{RT}+In10^6$
$E_a^{\prime }=E_a-RTIn10^6$
$E_a^{\prime }-E_a=-RTIn10^6$
$=-6RT\times 2.303$