The rate for the reaction RCl+NaOH(aq) xrightarrow[]ROH+NaCl is given by rate =k[RCl] , the freezing point of the reaction is:

Question

The rate for the reaction RCl+NaOH(aq) xrightarrow[]ROH+NaCl is given by rate =k[RCl] , the freezing point of the reaction is: (A) unaffacted by increasing the temp. of the reaction (B) decreased on increasing the temp. of the reaction (C) halved on reducing the concentration of RCl to half (D) doubled on doubling the concentration of NaOH

Tardigrade Admin · Accepted Answer

r=k[RCl] If [RCl]=(1/2) , then rate =(r/2)

Q. The rate for the reaction $RCl + N a O H (a q) RO H + N a Cl$ is given by rate $= k [RCl]$ , the freezing point of the reaction is:

unaffacted by increasing the temp. of the reaction

decreased on increasing the temp. of the reaction

halved on reducing the concentration of $RCl$ to half

doubled on doubling the concentration of $N a O H$

$r = k [RCl]$ If $[RCl] = \frac{1}{2}$ , then rate $= \frac{r}{2}$

Q. The rate for the reaction RCl+NaOH(aq)​ROH+NaCl is given by rate =k[RCl] , the freezing point of the reaction is:

unaffacted by increasing the temp. of the reaction

decreased on increasing the temp. of the reaction

halved on reducing the concentration of RCl to half

doubled on doubling the concentration of NaOH

r=k[RCl] If [RCl]=21​ , then rate =2r​

Q. The rate for the reaction $RCl + N a O H (a q) RO H + N a Cl$ is given by rate $= k [RCl]$ , the freezing point of the reaction is:

halved on reducing the concentration of $RCl$ to half

doubled on doubling the concentration of $N a O H$

$r = k [RCl]$ If $[RCl] = \frac{1}{2}$ , then rate $= \frac{r}{2}$