The rate constant of a first order reaction at 27° C is 10-3 min -1. The temperature coefficient of this reaction is 2. What is the rate constant (. in . min -1) at 17° C for this reaction?

Question

The rate constant of a first order reaction at 27° C is 10-3 min -1. The temperature coefficient of this reaction is 2. What is the rate constant (. in . min -1) at 17° C for this reaction? (A)  10-3 (B)  5× 10-4 (C)  2× 10-3 (D) 10-2

Tardigrade Admin · Accepted Answer

Temperature coefficient =(kt+10/kt) 2=(10-3/kt) kt=(10-3/2)=(10 × 10-4/2) =5 × 10-4

Q. The rate constant of a first order reaction at $2 7^{\circ} C$ is $1 0^{- 3} min^{- 1}$ . The temperature coefficient of this reaction is $2$ . What is the rate constant $($ in $min^{- 1})$ at $1 7^{\circ} C$ for this reaction?

$1 0^{- 3}$

$5 \times 1 0^{- 4}$

$2 \times 1 0^{- 3}$

$1 0^{- 2}$

Temperature coefficient $= \frac{k _{t} + 10}{k _{t}}$
$2 = \frac{1 0 ^{- 3}}{k _{t}}$
$k_{t} = \frac{1 0 ^{- 3}}{2} = \frac{10 \times 1 0 ^{- 4}}{2}$
$= 5 \times 1 0^{- 4}$

Q. The rate constant of a first order reaction at 27∘C is 10−3min−1. The temperature coefficient of this reaction is 2. What is the rate constant ( in min−1) at 17∘C for this reaction?

10−3

5×10−4

2×10−3

10−2