The rate constant K1 of a reaction is found to be double that of rate constant K2 of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature ( E1 and E2 ) can be represented as

Question

The rate constant K1 of a reaction is found to be double that of rate constant K2 of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature ( E1 and E2 ) can be represented as (A) E1>E2 (B) E1 < E2 (C) E1=E2 (D) None of these

Tardigrade Admin · Accepted Answer

K1=A1e- E1 / R T and K2=A2e- E2 / R T (K1/K2)=(A1/A2)e(. - E1 + E2 .) / R T As A1 and A2 are not given here so none of the relation is correct.

Q. The rate constant $K_{1}$ of a reaction is found to be double that of rate constant $K_{2}$ of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature ( $E_{1}$ and $E_{2}$ ) can be represented as

$E_{1} > E_{2}$

$E_{1} < E_{2}$

$E_{1} = E_{2}$

None of these

$K_{1} = A_{1} e^{- E_{1} / RT}$

and $K_{2} = A_{2} e^{- E_{2} / RT}$

$\frac{K _{1}}{K _{2}} = \frac{A _{1}}{A _{2}} e^{(- E_{1} + E_{2}) / RT}$

As $A_{1}$ and $A_{2}$ are not given here so none of the relation is correct.

Q. The rate constant K1​ of a reaction is found to be double that of rate constant K2​ of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature ( E1​ and E2​ ) can be represented as

E1​>E2​

E1​<E2​

E1​=E2​