The rate constant for a first order reaction is 2 × 10-2 min-1. The half-life period of reaction is

Question

The rate constant for a first order reaction is 2 × 10-2 min-1. The half-life period of reaction is (A) 69.3 min. (B) 34.65 min. (C) 17.37 min. (D) 3.46 min.

Tardigrade Admin · Accepted Answer

t1 2 =(0.693/k)=(0.693/2×10-2) =34.65 min.

Q. The rate constant for a first order reaction is $2 \times 1 0^{- 2} mi n^{- 1}$ . The half-life period of reaction is

$69.3 min$ .

$34.65 min$ .

$17.37 min$ .

$3.46 min$ .

$t_{12}$ $= \frac{0.693}{k} = \frac{0.693}{2 \times 1 0 ^{- 2}}$ $= 34.65 min$ .

Q. The rate constant for a first order reaction is 2×10−2min−1. The half-life period of reaction is

69.3min.

34.65min.

17.37min.

3.46min.

t12​ =k0.693​=2×10−20.693​ =34.65min.

Q. The rate constant for a first order reaction is $2 \times 1 0^{- 2} mi n^{- 1}$ . The half-life period of reaction is

$69.3 min$ .

$34.65 min$ .

$17.37 min$ .

$3.46 min$ .

$t_{12}$ $= \frac{0.693}{k} = \frac{0.693}{2 \times 1 0 ^{- 2}}$ $= 34.65 min$ .