The range of sec-1 x is

Question

The range of sec-1 x is (A) [ (-π/2) , (π/2) ] (B) ( (-π/2) , (π/2) ) (C) [0, π] (D) [0, π] - (π/2)

Tardigrade Admin · Accepted Answer

The range of sec-1 x =[0, π] - (π/2) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/97bdbe5f565a436f91420e40427a06da-.png" /> y = sec-1 x

Q. The range of $sec^{- 1} x$ is

$[\frac{- π}{2}, \frac{π}{2}]$

$(\frac{- π}{2}, \frac{π}{2})$

$[0, π]$

$[0, π] - {\frac{π}{2}}$

The range of $sec^{- 1} x$
$= [0, π] - {\frac{π}{2}}$

$y = sec^{- 1} x$

Q. The range of sec−1x is

[2−π​,2π​]

(2−π​,2π​)

[0,π]

[0,π]−{2π​}