Q.
The radius vector and linear momentum are respectively given by vectors 2i^+j^+k^ and 2i^−3j^+k^. Then the angular momentum is
1980
204
System of Particles and Rotational Motion
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Solution:
Given radius vector, r=2i^+j^+k^ Linear momentum, p=2i^−3j^+k^
As angular momentum, L=r×p=∣∣i^22j^1−3k^11∣∣ =i^(1−(−3))−j^(2−2)+k^(−6−2)=4i^−8k^