Q.
The radius of gyration of an uniform rod of length l about an axis passing through one of its ends and perpendicular to its length is
2148
243
System of Particles and Rotational Motion
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Solution:
Moment of inertia of rod of mass M and length l about its axis passing through one of its ends and perpendicular to it is I=31Ml2
As I=Mk2 where k is the radius of the gyration ∴Mk2=31Ml2 or k=3l