The Q factor of a series LCR circuit with L = 2 H, C = 32 μ F and R= 10 Ω is

Question

The Q factor of a series LCR circuit with L = 2 H, C = 32 μ F and R= 10 Ω is (A) 15 (B) 20 (C) 25 (D) 30

Tardigrade Admin · Accepted Answer

Here, L = 2 H, C= 32 μ F = 32 × 10-6 F, R = 10 Ω ∴ Resonance frequency, ωr=(1/√LC) =(1/√2×32×10-6) =(103/8) rad s-1 Quality factor (ωr L/R) =(103×2/8×10) =25

Q. The $Q$ factor of a series $L CR$ circuit with $L = 2 H$ , $C = 32 μ F$ and $R = 10 Ω$ is

$15$

$20$

$25$

$30$

Here, $L = 2 H$ ,
$C = 32 μ F = 32 \times 1 0^{- 6} F$ ,
$R = 10 Ω$
$∴$ Resonance frequency,
$ω_{r} = \frac{1}{L C}$
$= \frac{1}{2 \times 32 \times 1 0 ^{- 6}}$
$= \frac{1 0 ^{3}}{8} r a d s^{- 1}$
Quality factor $\frac{ω _{r} L}{R}$
$= \frac{1 0 ^{3} \times 2}{8 \times 10}$
$= 25$

Q. The Q factor of a series LCR circuit with L=2H, C=32μF and R=10Ω is

15

20

25

30