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Tardigrade
Question
Mathematics
The proposition p arrow ∼(p ∧ ∼ q) is
Q. The proposition
p
→∼
(
p
∧
∼
q
)
is
246
151
Mathematical Reasoning
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A
A contradiction
B
A tautology
C
Either a tautology or a contradiction
D
Neither a tautology nor a contradiction
Solution:
p
→∼
(
p
∧
∼
q
)
≅∼
p
∨
∼
(
p
∧
∼
q
)
≅∼
p
∨
(
∼
p
∨
q
)
≅∼
p
∨
q
Clearly, it is neither a tautology nor a contradiction