The proportion of the offsprings obtained from the cross AABBCC × AaBbCc will be completely heterozygous for all genes segregated independently will be

Question

The proportion of the offsprings obtained from the cross AABBCC × AaBbCc will be completely heterozygous for all genes segregated independently will be (A) 1 / 8 (B) 1 / 4 (C) 1 / 2 (D) 1 / 16

Tardigrade Admin · Accepted Answer

As per Mendel's Law of Segregation "alleles segregate randomly into gametes: When gametes are formed, each allele of one parent segregates randomly into the gametes, such that half of the parent's gametes carry each allele."
The cross between parents with genotype produces the following progenies -

A BBCC \times A a B b C c

AABBCC
AABBCc
AABbCC
AABbCc
AaBBCC
AaBbCc
AaBBCc
AaBbCC
Progeny with genotype heterozygous for all gene is 1 out of 8 types. Thus, probability is

1/8

Q. The proportion of the offsprings obtained from the cross $AA BBCC \times A a B b C c$ will be completely heterozygous for all genes segregated independently will be

$1/8$

$1/4$

$1/2$

$1/16$

Q. The proportion of the offsprings obtained from the cross AABBCC×AaBbCc will be completely heterozygous for all genes segregated independently will be

1/8

1/4

1/2

1/16

Q. The proportion of the offsprings obtained from the cross $AA BBCC \times A a B b C c$ will be completely heterozygous for all genes segregated independently will be

$1/8$

$1/4$

$1/2$

$1/16$