The probability of getting 10 in a single throw of three fair dice is :

Question

The probability of getting 10 in a single throw of three fair dice is : (A) (1/6) (B) (1/8) (C) (1/9) (D) (1/5)

Tardigrade Admin · Accepted Answer

Exhaustive no. of cases =63 10 can appear on three dice either as distinct number as following (1,3,6) ;(1,4,5) ;(2,3,5) and each can occur in 3 ! ways. Or 10 can appear on three dice as repeated digits as following (2,2,6),(2,4,4),(3,3,4) and each can occur in (3 !/2 !) ways. ∴ No. of favourable cases =3 × 3 !+3 × (3 !/2 !)=27

Q. The probability of getting $10$ in a single throw of three fair dice is :

$\frac{1}{6}$

$\frac{1}{8}$

$\frac{1}{9}$

$\frac{1}{5}$

Q. The probability of getting 10 in a single throw of three fair dice is :

61​

81​

91​

51​

Q. The probability of getting $10$ in a single throw of three fair dice is :

$\frac{1}{6}$

$\frac{1}{8}$

$\frac{1}{9}$

$\frac{1}{5}$