The pressure of a gas is equal to

Question

The pressure of a gas is equal to (A) the total translation kinetic energy of all the molecules in unit volume (B) the total kinetic energy of all the molecules in unit volume (C) two thirds of the total translational kinetic energy of all the molecules in unit volume (D) two-thirds of the total kinetic energy of all the molecules in unit volume

Tardigrade Admin · Accepted Answer

P=(m N barc2/3 V)=(2/3) ⋅ (1/2) (M barc2/V)=(2/3)((1/2) ρ barc2) or P=(2/3) E

Q. The pressure of a gas is equal to

the total translation kinetic energy of all the molecules in unit volume

the total kinetic energy of all the molecules in unit volume

two thirds of the total translational kinetic energy of all the molecules in unit volume

two-thirds of the total kinetic energy of all the molecules in unit volume

$P = \frac{m N c ˉ ^{2}}{3 V} = \frac{2}{3} \cdot \frac{1}{2} \frac{M c ˉ ^{2}}{V} = \frac{2}{3} (\frac{1}{2} ρ \overset{c}{ˉ}^{2})$
or $P = \frac{2}{3} E$

Q. The pressure of a gas is equal to

the total translation kinetic energy of all the molecules in unit volume

the total kinetic energy of all the molecules in unit volume

two thirds of the total translational kinetic energy of all the molecules in unit volume

two-thirds of the total kinetic energy of all the molecules in unit volume

P=3VmNcˉ2​=32​⋅21​VMcˉ2​=32​(21​ρcˉ2) or P=32​E

$P = \frac{m N c ˉ ^{2}}{3 V} = \frac{2}{3} \cdot \frac{1}{2} \frac{M c ˉ ^{2}}{V} = \frac{2}{3} (\frac{1}{2} ρ \overset{c}{ˉ}^{2})$
or $P = \frac{2}{3} E$