The pressure increases on the fluid in a syringe when a nurse applies a force of 42 N to the syringes circular piston, which has a radius of 1.1 cm.

Question

The pressure increases on the fluid in a syringe when a nurse applies a force of 42 N to the syringes circular piston, which has a radius of 1.1 cm. (A)  1.1× 105Pa  (B)  11× 105Pa (C)  1.1× 107Pa  (D)  1.1× 101Pa

Tardigrade Admin · Accepted Answer

Force applied =42 N radius =1.1 cm Pressure =(F/A)=(42/3.14 ×(1.1 × 10-2)2) =1.1 × 105 Pa

Q. The pressure increases on the fluid in a syringe when a nurse applies a force of $42 N$ to the syringes circular piston, which has a radius of $1.1 c m$ .

$1.1 \times 1 0^{5} P a$

$11 \times 1 0^{5} P a$

$1.1 \times 1 0^{7} P a$

$1.1 \times 1 0^{1} P a$

Force applied $= 42 N$
radius $= 1.1 c m$
Pressure $= \frac{F}{A} = \frac{42}{3.14 \times ( 1.1 \times 1 0 ^{- 2} ) ^{2}}$
$= 1.1 \times 1 0^{5} P a$

Q. The pressure increases on the fluid in a syringe when a nurse applies a force of 42N to the syringes circular piston, which has a radius of 1.1cm.

1.1×105Pa

11×105Pa

1.1×107Pa

1.1×101Pa