The power of lens used by a short-sighted person is -2 D. Find the maximum distance of an object, which he can see without spectacles

Question

The power of lens used by a short-sighted person is -2 D. Find the maximum distance of an object, which he can see without spectacles (A) 25 cm (B) 50 cm (C) 100 cm (D) 10 cm

Tardigrade Admin · Accepted Answer

P=-2D Focal length of the lens (f)=(1/P) =(1/-2)m=-(100/2)cm Therefore, person can see up to distance 50cm .

Q. The power of lens used by a short-sighted person is -2 D. Find the maximum distance of an object, which he can see without spectacles

25 cm

50 cm

100 cm

10 cm

$P = - 2 D$ Focal length of the lens $(f) = \frac{1}{P}$ $= \frac{1}{- 2} m = - \frac{100}{2} c m$ Therefore, person can see up to distance $50 c m$ .

Q. The power of lens used by a short-sighted person is -2 D. Find the maximum distance of an object, which he can see without spectacles

25 cm

50 cm

100 cm

10 cm

P=−2D Focal length of the lens (f)=P1​ =−21​m=−2100​cm Therefore, person can see up to distance 50cm .

$P = - 2 D$ Focal length of the lens $(f) = \frac{1}{P}$ $= \frac{1}{- 2} m = - \frac{100}{2} c m$ Therefore, person can see up to distance $50 c m$ .