Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
The potential difference in volt across the resistance R., in the circuit shown in figure, is (R1=15 Ω, R2=15 Ω, R3=30 Ω, R4=35 Ω)
Q. The potential difference in volt across the resistance R., in the circuit shown in figure, is
(
R
1
=
15
Ω
,
R
2
=
15
Ω
,
R
3
=
30
Ω
,
R
4
=
35
Ω
)
2393
225
Bihar CECE
Bihar CECE 2010
Electromagnetic Induction
Report Error
A
5
14%
B
7.5
29%
C
15
50%
D
12.5
7%
Solution:
Total resistance of the circuit
R
+
(
R
1
+
R
2
)
+
R
3
(
R
1
+
R
2
)
×
R
3
35
+
(
15
+
15
)
+
30
(
15
+
15
)
×
30
=
35
+
30
+
30
30
×
30
=
50
Ω
Current in circuit,
i
=
50
50
=
1
A
Current through
R
3
i
=
i
2
=
2
1
A
Potential difference across
R
3
=
i
×
R
3
=
2
1
×
30
=
15
V