The position-time (x-t) graph of a moving body of mass 2 kg is shown in the figure. impulse on the body at t = 4 s is

Question

The position-time (x-t) graph of a moving body of mass 2 kg is shown in the figure. impulse on the body at t = 4 s is (A) 1.5 kg ms-1 (B) -1.5 kg - ms -1 (C) 1 kg - ms -1 (D) 2 kg ms-1

Tardigrade Admin · Accepted Answer

Here, mass of the body, m=2 kg and time, t=4 s Impulse =pf-pi where, pi= initial momentum, pf= final momentum Impulse m vf-m vi=m(vf-vi) (∵ p=m v) As from the graph, vf=(3-3/8-4)=0 and vi=(3-0/4-0)=(3/4) Impulse =2 ×(0-(3/4)) =-1.5 kg = ms -1

Q. The position-time $(x - t)$ graph of a moving body of mass $2 k g$ is shown in the figure. impulse on the body at $t = 4 s$ is

$1.5 k g m s^{- 1}$

$- 1.5 k g - m s^{- 1}$

$1 k g - m s^{- 1}$

$2 k g m s^{- 1}$

Q. The position-time (x−t) graph of a moving body of mass 2kg is shown in the figure. impulse on the body at t=4s is

1.5kgms−1

−1.5kg−ms−1

1kg−ms−1

2kgms−1

Here, mass of the body, m=2kg and time, t=4s Impulse =pf​−pi​ where, pi​= initial momentum, pf​= final momentum Impulse mvf​−mvi​=m(vf​−vi​) (∵p=mv) As from the graph, vf​=8−43−3​=0 and vi​=4−03−0​=43​ Impulse =2×(0−43​) =−1.5kg=ms−1

Q. The position-time $(x - t)$ graph of a moving body of mass $2 k g$ is shown in the figure. impulse on the body at $t = 4 s$ is

$1.5 k g m s^{- 1}$

$- 1.5 k g - m s^{- 1}$

$1 k g - m s^{- 1}$

$2 k g m s^{- 1}$