The position of both an electron and helium atom is known within 1.0 nm. The momentum of the electron is known within 5.0 × 10-26 kg ms -1. The minimum uncertainty in the measurement of the momentum of the helium atom is

Question

The position of both an electron and helium atom is known within 1.0 nm. The momentum of the electron is known within 5.0 × 10-26 kg ms -1. The minimum uncertainty in the measurement of the momentum of the helium atom is (A) 50 kg ms -1 (B) 5.0 × 10-26 kg ms -1 (C) 80 kg ms -1 (D) 80 × 10-26 kg ms -1

Tardigrade Admin · Accepted Answer

By Heisenberg's uncertainty principle Δ x × Δ p ≥ (h/4 π) when the position of electron and helium atom is same and momentum of electron is known within a range, therefore the momentum of helium atom is also equal to the momentum of electron, i.e. 5 × 10-26 kg m s -1

Q. The position of both an electron and helium atom is known within $1.0 nm$ . The momentum of the electron is known within $5.0 \times 1 0^{- 26} k g m s^{- 1}$ . The minimum uncertainty in the measurement of the momentum of the helium atom is

$50 k g m s^{- 1}$

$5.0 \times 1 0^{- 26} k g m s^{- 1}$

$80 k g m s^{- 1}$

$80 \times 1 0^{- 26} k g m s^{- 1}$

Q. The position of both an electron and helium atom is known within 1.0nm. The momentum of the electron is known within 5.0×10−26kgms−1. The minimum uncertainty in the measurement of the momentum of the helium atom is

50kgms−1

5.0×10−26kgms−1

80kgms−1

80×10−26kgms−1

By Heisenberg's uncertainty principle Δx×Δp≥4πh​ when the position of electron and helium atom is same and momentum of electron is known within a range, therefore the momentum of helium atom is also equal to the momentum of electron, i.e. 5×10−26kgms−1

Q. The position of both an electron and helium atom is known within $1.0 nm$ . The momentum of the electron is known within $5.0 \times 1 0^{- 26} k g m s^{- 1}$ . The minimum uncertainty in the measurement of the momentum of the helium atom is

$50 k g m s^{- 1}$

$5.0 \times 1 0^{- 26} k g m s^{- 1}$

$80 k g m s^{- 1}$

$80 \times 1 0^{- 26} k g m s^{- 1}$