The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within 5.0 × 10- 26 textkgms- 1 . The minimum uncertainty in the measurement of the momentum of the helium atom is

Question

The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within 5.0 × 10- 26 textkgms- 1 . The minimum uncertainty in the measurement of the momentum of the helium atom is (A) 6.0× 10- 26 kgms- 1 (B) 60 kgms- 1 (C) 50 kgms- 1 (D) 5.0× 10- 26 kgms- 1

Tardigrade Admin · Accepted Answer

According to uncertainty principle the product of uncertainty in position and uncertainty in momentum is constant for a particle.
i.e.,

Δ x \times Δ p = \frac{h}{4 π}

As

Δ x = 1.0

nm for both electron and helium atom, so

Δ p

is also same for both the particle.
Thus, uncertainty in momentum of the helium atom is also

5.0 \times 1 0^{- 26} k g m s^{- 1}

.

Q. The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within $5.0 \times 1 0^{- 26} kgms^{- 1} .$ The minimum uncertainty in the measurement of the momentum of the helium atom is

$6.0 \times 1 0^{- 26}$ $k g m s^{- 1}$

$60$ $k g m s^{- 1}$

$50$ $k g m s^{- 1}$

$5.0 \times 1 0^{- 26}$ $k g m s^{- 1}$

Q. The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within 5.0×10−26kgms−1. The minimum uncertainty in the measurement of the momentum of the helium atom is

6.0×10−26 kgms−1

60 kgms−1

50 kgms−1

5.0×10−26 kgms−1

Q. The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within $5.0 \times 1 0^{- 26} kgms^{- 1} .$ The minimum uncertainty in the measurement of the momentum of the helium atom is

$6.0 \times 1 0^{- 26}$ $k g m s^{- 1}$

$60$ $k g m s^{- 1}$

$50$ $k g m s^{- 1}$

$5.0 \times 1 0^{- 26}$ $k g m s^{- 1}$