Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The point on the curve 6y = x3 + 2 at which y - co-ordinate is changing 8 times as fast as x- co-ordinate is
Q. The point on the curve
6
y
=
x
3
+
2
at which
y
- co-ordinate is changing
8
times as fast as
x
- co-ordinate is ______________
1670
179
MHT CET
MHT CET 2016
Application of Derivatives
Report Error
A
(
4
,
11
)
52%
B
(
4
,
−
11
)
19%
C
(
−
4
,
11
)
17%
D
(
−
4
,
−
11
)
12%
Solution:
Given,
6
y
=
x
3
+
2
…
(
i
)
and
Δ
y
=
8Δ
x
On differentiating both sides of Eq. (i) w.r.t.
x
, we get
d
x
6
d
y
=
3
x
2
⇒
d
x
d
y
=
2
1
x
2
∵
Δ
y
=
d
x
d
y
Δ
x
⇒
8Δ
x
=
2
1
x
2
Δ
x
⇒
x
2
=
16
⇒
x
=
±
4
When
x
=
4
,
6
y
=
(
4
)
3
+
2
⇒
6
y
=
66
⇒
y
=
11
Hence, required point is
(
4
,
11
)