The phase difference between two waves reaching a point is π / 2. What is the resultant amplitude if the individual amplitudes are 3 mm 4 mm ?

Question

The phase difference between two waves reaching a point is π / 2. What is the resultant amplitude if the individual amplitudes are 3 mm 4 mm ? (A) 5 mm (B) 6 mm (C) 7 mm (D) 1 mm

Tardigrade Admin · Accepted Answer

According to the relation, R =√ a 2+ b 2+2 ab cos φ R=√(3)2+(4)2+2 × 3 × 4 cos (π/2) R=√32+42 ⇒ R=√9+16=5 mm

Q. The phase difference between two waves reaching a point is $π /2$ . What is the resultant amplitude if the individual amplitudes are $3 mm &4 mm ?$

$5 mm$

$6 mm$

$7 mm$

$1 mm$

According to the relation, $R = a^{2} + b^{2} + 2 ab cos ϕ$
$R = (3)^{2} + (4)^{2} + 2 \times 3 \times 4 cos \frac{π}{2}$
$R = 3^{2} + 4^{2}$
$\Rightarrow R = 9 + 16 = 5 mm$

Q. The phase difference between two waves reaching a point is π/2. What is the resultant amplitude if the individual amplitudes are 3mm&4mm?

5mm

6mm

7mm

1mm