Question

The $pH$ of the solution produced by mixing equal volume of $2.0\times 10^{-3}MHCl{O}_4$ and $1.0\times 10^{-2}MKCl{O}_4$ is

• A. $2.7$
• B. $2.3$
• C. $3.0$
• D. $1.0$

Answer 1

Answer: (C)

$KCl{O}_4$ being a neutral salt does not affect the nature of solution
$[HCl{O}_4]=\frac{2.0\times 10^{-3}}{2}$
$=1.0\times 10^{-3}=[H^{+}]$
$PH=-log[H^{+}]=-log1.0\times 10^{-3}$
$=3$