The pH of resultant solution of 20 mL of 0.1 M textCH text3 textCOOH and 20 mL of 0.1 M textCH text3 textCOONa is

Question

The pH of resultant solution of 20 mL of 0.1 M textCH text3 textCOOH and 20 mL of 0.1 M textCH text3 textCOONa is (A) pKa1 (B) pKa2 (C) (p Ka1 + p Ka2/2) (D) 2

Tardigrade Admin · Accepted Answer

[ textCH text3 textCOOH] text= [ textCH text3 textCOONa] The resultant solution will be a buffer solution. So pH=pKa2+log[(CH3 - COOH/CH3 - COONa)] &hellip;(ii) From (i) and (ii) pH=pKa2 .

Q. The pH of resultant solution of 20 mL of 0.1 M $CH_{3} COOH$ and 20 mL of 0.1 M $CH_{3} COONa$ is

$p K_{a_{1}}$

$p K_{a_{2}}$

$\frac{p K _{a_{1}} + p K _{a_{2}}}{2}$

2

$[CH_{3} COOH] = [CH_{3} COONa]$
The resultant solution will be a buffer solution.
So $p H = p K_{a_{2}} + l o g [\frac{C H _{3} - COO H}{C H _{3} - COON a}]$ …(ii)
From (i) and (ii)
$p H = p K_{a_{2}}$ .

Q. The pH of resultant solution of 20 mL of 0.1 M CH3​COOH and 20 mL of 0.1 M CH3​COONa is

pKa1​​

pKa2​​

2pKa1​​+pKa2​​​

2

[CH3​COOH]=[CH3​COONa] The resultant solution will be a buffer solution. So pH=pKa2​​+log[CH3​−COONaCH3​−COOH​] …(ii) From (i) and (ii) pH=pKa2​​ .

Q. The pH of resultant solution of 20 mL of 0.1 M $CH_{3} COOH$ and 20 mL of 0.1 M $CH_{3} COONa$ is

$p K_{a_{1}}$

$p K_{a_{2}}$

$\frac{p K _{a_{1}} + p K _{a_{2}}}{2}$

$[CH_{3} COOH] = [CH_{3} COONa]$
The resultant solution will be a buffer solution.
So $p H = p K_{a_{2}} + l o g [\frac{C H _{3} - COO H}{C H _{3} - COON a}]$ …(ii)
From (i) and (ii)
$p H = p K_{a_{2}}$ .