The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 mL of 1 M NaOH is x × 10-4. The value of x is (Nearest integer) [ log 2.5=0.3979]

Question

The pH of a solution obtained by mixing 50 mL of 1 M HCl and 30 mL of 1 M NaOH is x × 10-4. The value of x is (Nearest integer) [ log 2.5=0.3979] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/d9e5dca96f62101016a50d1dd65a59ed-.png" /> [ HCl ]=(20/80)=(1/4) M =2.5 × 10-1 M pH =- log 2.15 × 10-1=1-0.3979=0.6021 pH =6021 × 10-4

Q. The $p H$ of a solution obtained by mixing $50 m L$ of $1 M H Cl$ and $30 m L$ of $1 M N a O H$ is $x \times 1 0^{- 4}$ . The value of $x$ is _______ (Nearest integer) $[lo g 2.5 = 0.3979]$

$[H Cl] = \frac{20}{80} = \frac{1}{4} M = 2.5 \times 1 0^{- 1} M$
$p H = - lo g 2.15 \times 1 0^{- 1} = 1 - 0.3979 = 0.6021$
$p H = 6021 \times 1 0^{- 4}$

Q. The pH of a solution obtained by mixing 50mL of 1MHCl and 30mL of 1MNaOH is x×10−4. The value of x is _______ (Nearest integer) [log2.5=0.3979]

[HCl]=8020​=41​M=2.5×10−1M pH=−log2.15×10−1=1−0.3979=0.6021 pH=6021×10−4

Q. The $p H$ of a solution obtained by mixing $50 m L$ of $1 M H Cl$ and $30 m L$ of $1 M N a O H$ is $x \times 1 0^{- 4}$ . The value of $x$ is _______ (Nearest integer) $[lo g 2.5 = 0.3979]$

$[H Cl] = \frac{20}{80} = \frac{1}{4} M = 2.5 \times 1 0^{- 1} M$
$p H = - lo g 2.15 \times 1 0^{- 1} = 1 - 0.3979 = 0.6021$
$p H = 6021 \times 1 0^{- 4}$