Question

The percentage $s$-character in $s{p}^3$-hybridisation is

• A. $25\%s$-character
• B. $50\%s$-character
• C. $75\%s$-character
• D. $100\%s$-character

Answer 1

Answer: (A)

In $s{p}^3$-hybrid orbital, $s$-character is
$=\frac{1}{4}\times 100=25\%$