The partial pressure of carbon monoxide from the following data will be CaCO 3(s) xrightleftharpoonsΔ CaO (s)+ CO 2 uparrow ; Kp1=8 × 10-2 CO 2(g)+ C (s) leftharpoons 2 CO (g) ; Kp2=2

Question

The partial pressure of carbon monoxide from the following data will be CaCO 3(s) xrightleftharpoonsΔ CaO (s)+ CO 2 uparrow ; Kp1=8 × 10-2 CO 2(g)+ C (s) leftharpoons 2 CO (g) ; Kp2=2 (A) 0.2 atm (B) 0.6 atm (C) 0.8 atm (D) 0.4 atm

Tardigrade Admin · Accepted Answer

CaCO 3(s) xrightleftharpoonsΔCaO (s)+ CO 2 uparrow ; Kp1=8 × 10-2 CO 2(g)+ C (s) longrightarrow 2 CO (g) ; Kp2=2 Thus, for the reaction, CaCO 3(s)+ C (s) leftharpoons CaO (s)+2 CO (g) Kp prime=Kp1 × Kp2=8 × 10-2 × 2=16 × 10-2 ∴ Kp prime=(p CO (g))2 ⇒ p CO =√Kp prime=√16 × 10-2 =4 × 10-1=0.4 atm

Q. The partial pressure of carbon monoxide from the following data will be
$C a C O_{3} (s) Δ C a O (s) + C O_{2} ↑; K_{p_{1}} = 8 \times 1 0^{- 2}$
$C O_{2} (g) + C (s) ⇌ 2 CO (g); K_{p_{2}} = 2$

$0.2 a t m$

$0.6 a t m$

$0.8 a t m$

$0.4 a t m$

Q. The partial pressure of carbon monoxide from the following data will be CaCO3​(s)Δ​CaO(s)+CO2​↑;Kp1​​=8×10−2 CO2​(g)+C(s)⇌2CO(g);Kp2​​=2

0.2atm

0.6atm

0.8atm

0.4atm

CaCO3​(s)Δ​CaO(s)+CO2​↑;Kp1​​=8×10−2 CO2​(g)+C(s)⟶2CO(g);Kp2​​=2 Thus, for the reaction, CaCO3​(s)+C(s)⇌CaO(s)+2CO(g) Kp′​=Kp1​​×Kp2​​=8×10−2×2=16×10−2 ∴Kp′​=(pCO​(g))2 ⇒pCO​=Kp′​​=16×10−2​ =4×10−1=0.4atm

Q. The partial pressure of carbon monoxide from the following data will be
$C a C O_{3} (s) Δ C a O (s) + C O_{2} ↑; K_{p_{1}} = 8 \times 1 0^{- 2}$
$C O_{2} (g) + C (s) ⇌ 2 CO (g); K_{p_{2}} = 2$

$0.2 a t m$

$0.6 a t m$

$0.8 a t m$

$0.4 a t m$