The P - P - P angle in P 4 molecule and S - S - S angle in S 8 molecule is (in degree) respectively:

Question

The P - P - P angle in P 4 molecule and S - S - S angle in S 8 molecule is (in degree) respectively: (A) 60° , 107° (B) 107° , 60° (C) 40° , 60° (D) 60° , 40°

Tardigrade Admin · Accepted Answer

InP 4 molecule, the four Sp 3 hybridized phosphorous atoms lie at the corners of a regular tetrahedron with angle PPP =60°. In S 8 molecule, S - S - S angle is 107°.

Q. The $P - P - P$ angle in $P_{4}$ molecule and $S - S - S$ angle in $S_{8}$ molecule is (in degree) respectively:

$6 0^{\circ}, 10 7^{\circ}$

$10 7^{\circ}, 6 0^{\circ}$

$4 0^{\circ}, 6 0^{\circ}$

$6 0^{\circ}, 4 0^{\circ}$

InP $_{4}$ molecule, the four $S p^{3}$ hybridized phosphorous atoms lie at the corners of a regular tetrahedron with $∠ PPP = 6 0^{\circ}$ .
In $S_{8}$ molecule, $S - S - S$ angle is $10 7^{\circ}$ .

Q. The P−P−P angle in P4​ molecule and S−S−S angle in S8​ molecule is (in degree) respectively:

60∘,107∘

107∘,60∘

40∘,60∘

60∘,40∘