The oxygen-carrying protein known as haemoglobin is 0.335% Fe by mass and contains four Fe atoms per haemoglobin molecule. Calculate the molecular weight of this protein.

Question

The oxygen-carrying protein known as haemoglobin is 0.335% Fe by mass and contains four Fe atoms per haemoglobin molecule. Calculate the molecular weight of this protein. (A) 66 g mol-1 (B) 66.6 g mol-1 (C) 6.6683 ×104 g mol-1 (D) 666 g mol-1

Tardigrade Admin · Accepted Answer

Percentage by mass of Fe in haemoglobin is 0.335%.
So,

\frac{4 \times A t wt o f F e}{M o l wt o f ha e m o g l o bin} \times 100 = % F e

or

\frac{4 \times 55.847}{M o l wt o f ha e m o g l o bin} \times 100 = 0.335

or Mol. wt. of haemoglobin

= \frac{400 \times 55.847}{0.335} = 66683 g m o l^{- 1}

Q. The oxygen-carrying protein known as haemoglobin is 0.335% Fe by mass and contains four Fe atoms per haemoglobin molecule. Calculate the molecular weight of this protein.

$66 g m o l^{- 1}$

$66.6 g m o l^{- 1}$

$6.6683 \times 1 0^{4} g m o l^{- 1}$

$666 g m o l^{- 1}$

Q. The oxygen-carrying protein known as haemoglobin is 0.335% Fe by mass and contains four Fe atoms per haemoglobin molecule. Calculate the molecular weight of this protein.

66gmol−1

66.6gmol−1

6.6683×104gmol−1

666gmol−1

Percentage by mass of Fe in haemoglobin is 0.335%. So, Molwtofhaemoglobin4×AtwtofFe​×100=%Fe or Molwtofhaemoglobin4×55.847​×100=0.335 or Mol. wt. of haemoglobin =0.335400×55.847​=66683gmol−1

$66 g m o l^{- 1}$

$66.6 g m o l^{- 1}$

$6.6683 \times 1 0^{4} g m o l^{- 1}$

$666 g m o l^{- 1}$