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Question
Chemistry
The oxidation state of Fe in K4[Fe(CN)6] is
Q. The oxidation state of Fe in
K
4
[
F
e
(
CN
)
6
]
is
2491
234
Redox Reactions
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A
+
2
62%
B
+
3
14%
C
+
4
12%
D
+
6
12%
Solution:
K
4
[
F
e
(
CN
)
6
]
+
4
+
x
+
6
(
−
1
)
=
0
or
x
=
+
2