Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The oxidation number of Fe in Na 2[ Fe ( CN )5 NO ] is
Q. The oxidation number of
F
e
in
N
a
2
[
F
e
(
CN
)
5
NO
]
is
376
238
Redox Reactions
Report Error
A
+
2
B
+
1
C
+
3
D
−
2
Solution:
Correct answer is (a)
+
2
