Question

The oxidation number of $C$ atom in $C{H}_{2}C{l}_2$ and $CC{l}_4$ are respectively

• A. $-2$ and $-4$
• B. $0$ and $-4$
• C. $0$ and $4$
• D. $2$ and $4$

Answer 1

Answer: (C)

Let the oxidation number of $C$ is $x$

$C{H}_{2}C{l}_2$

$x+2(+1)+2(-1)=0$

$x+2-2=0$

$x=0$

$CC{l}_4$

$x+4(-1)=0$

$x-4=0$

$x=4$