The order of the differential equation of all circles whose radius is 4, is ..........

Question

The order of the differential equation of all circles whose radius is 4, is .......... (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

Let equation of all circles having centre (a, b) and given radius is 4, is (x-a)2+(y-b)2=4 Here, number of arbitrary constant in two (a, b) so its order is 2 .

Q. The order of the differential equation of all circles whose radius is $4$ , is ..........

$1$

$2$

$3$

$4$

Let equation of all circles having centre $(a, b)$ and given radius is $4,$ is
$(x - a)^{2} + (y - b)^{2} = 4$
Here, number of arbitrary constant in two $(a, b)$ so its order is $2.$

Q. The order of the differential equation of all circles whose radius is 4, is ..........

1

2

3

4

Let equation of all circles having centre (a,b) and given radius is 4, is (x−a)2+(y−b)2=4 Here, number of arbitrary constant in two (a,b) so its order is 2.

Q. The order of the differential equation of all circles whose radius is $4$ , is ..........

$1$

$2$

$3$

$4$

Let equation of all circles having centre $(a, b)$ and given radius is $4,$ is
$(x - a)^{2} + (y - b)^{2} = 4$
Here, number of arbitrary constant in two $(a, b)$ so its order is $2.$