The order of increasing freezing point of C2H5OH, Ba3(PO4)2, Na2SO4, KCl and Li3PO4 is

Question

The order of increasing freezing point of C2H5OH, Ba3(PO4)2, Na2SO4, KCl and Li3PO4 is (A) Ba3(PO4)2 < Na2SO4 < Li3PO4 < C2H5OH < KCl (B) Ba3(PO4)2 < C2H5OH < Li3PO4 < Na2SO4 < KCl (C) C2H5OH < KCl < Na2SO4 < Ba3(PO4)2 < Li3PO4 (D) Ba3(PO4)2 < Li3PO4 < Na2SO4 < KCl < C2H5OH

Tardigrade Admin · Accepted Answer

ΔTf ∝ i i for C2H5OH = 1, i for Ba3(PO4)2 = 5, i for Na 2SO4 = 3, i for KCl = 2, i for Li3PO4 = 4 Thus, depression in freezing point will be in order: C2H5OH < KCl < Na2SO4 < Li3PO4 < Ba3(PO4)2 and freezing point will be in order: Ba3(PO4)2 < Li3PO4 < Na2SO4 < KCl < C2H5OH

Q. The order of increasing freezing point of $C_{2} H_{5} O H, B a_{3} (P O_{4})_{2}, N a_{2} S O_{4}, K Cl$ and $L i_{3} P O_{4}$ is

$B a_{3} (P O_{4})_{2} < N a_{2} S O_{4} < L i_{3} P O_{4} < C_{2} H_{5} O H < K Cl$

$B a_{3} (P O_{4})_{2} < C_{2} H_{5} O H < L i_{3} P O_{4} < N a_{2} S O_{4} < K Cl$

$C_{2} H_{5} O H < K Cl < N a_{2} S O_{4} < B a_{3} (P O_{4})_{2} < L i_{3} P O_{4}$

$B a_{3} (P O_{4})_{2} < L i_{3} P O_{4} < N a_{2} S O_{4} < K Cl < C_{2} H_{5} O H$

Q. The order of increasing freezing point of C2​H5​OH,Ba3​(PO4​)2​,Na2​SO4​,KCl and Li3​PO4​ is

Ba3​(PO4​)2​<Na2​SO4​<Li3​PO4​<C2​H5​OH<KCl

Ba3​(PO4​)2​<C2​H5​OH<Li3​PO4​<Na2​SO4​<KCl

C2​H5​OH<KCl<Na2​SO4​<Ba3​(PO4​)2​<Li3​PO4​

Ba3​(PO4​)2​<Li3​PO4​<Na2​SO4​<KCl<C2​H5​OH

Q. The order of increasing freezing point of $C_{2} H_{5} O H, B a_{3} (P O_{4})_{2}, N a_{2} S O_{4}, K Cl$ and $L i_{3} P O_{4}$ is

$B a_{3} (P O_{4})_{2} < N a_{2} S O_{4} < L i_{3} P O_{4} < C_{2} H_{5} O H < K Cl$

$B a_{3} (P O_{4})_{2} < C_{2} H_{5} O H < L i_{3} P O_{4} < N a_{2} S O_{4} < K Cl$

$C_{2} H_{5} O H < K Cl < N a_{2} S O_{4} < B a_{3} (P O_{4})_{2} < L i_{3} P O_{4}$

$B a_{3} (P O_{4})_{2} < L i_{3} P O_{4} < N a_{2} S O_{4} < K Cl < C_{2} H_{5} O H$