The order of differential equation of all circles of given radius 'a' is

Question

The order of differential equation of all circles of given radius 'a' is  (A) 4 (B) 2 (C) 1 (D) 3

Tardigrade Admin · Accepted Answer

Let the centre of circle be ( h , k ) and radius a, then its equation will be (x-h)2+(y-k)2=a2 Since, there are two parameters h and k . So, the differential equation is of order 2

Q. The order of differential equation of all circles of given radius $^{'} a^{'}$ is _____

4

2

1

3

Let the centre of circle be $(h, k)$ and radius $a$ , then its equation will be
$(x - h)^{2} + (y - k)^{2} = a^{2}$
Since, there are two parameters $h$ and $k .$ So, the differential equation is of order 2

Q. The order of differential equation of all circles of given radius ′a′ is _____

4

2

1

3

Let the centre of circle be (h,k) and radius a, then its equation will be (x−h)2+(y−k)2=a2 Since, there are two parameters h and k. So, the differential equation is of order 2

Q. The order of differential equation of all circles of given radius $^{'} a^{'}$ is _____

Let the centre of circle be $(h, k)$ and radius $a$ , then its equation will be
$(x - h)^{2} + (y - k)^{2} = a^{2}$
Since, there are two parameters $h$ and $k .$ So, the differential equation is of order 2