Question

The oithocentre and the centroid of $\Delta ABC$ are (5.8) and $\left(3,\frac{14}{3}\right)$ respectively. The equation of the side BC is $x-y=0$. Given that the image of the orthocentre of a triangle with respect to any side lies on the circumcircle of that triangle, then the diameter of the circumcircle of $\Delta ABC$ is

• A. $\sqrt{10}$
• B. $2\sqrt{10}$
• C. $4\sqrt{10}$
• D. $8\sqrt{10}$

Answer 1

Answer: (C)

Correct answer is (c) $4\sqrt{10}$