Question

The number of ways in which $5$ girls and $3$ boys can be seated in a row so that no two boys are together is

• A. 14040
• B. 14440
• C. 14000
• D. 14400

Answer 1

Answer: (D)

$5$ girls are arranged in $51$ ways where as in $6$ Gaps $3$ boys can be arranged in ${}^6{p}_3$ ways.
$\therefore$ Number of ways $=5{!}^6{p}_3=14400$