The number of ways in which 5 boys and 5 girls can be seated for a photograph so that no two girls sit next to each other is

Question

The number of ways in which 5 boys and 5 girls can be seated for a photograph so that no two girls sit next to each other is (A)  6! 5!  (B)  (5!)2  (C)  (10!/(5!))  (D)  (10!/(5!)2)

Tardigrade Admin · Accepted Answer

Required number of ways =5!× 6!

Q. The number of ways in which $5$ boys and $5$ girls can be seated for a photograph so that no two girls sit next to each other is

$6! 5!$

$(5!)^{2}$

$\frac{10 !}{( 5 !)}$

$\frac{10 !}{( 5 !) ^{2}}$

Required number of ways $= 5! \times 6!$

Q. The number of ways in which 5 boys and 5 girls can be seated for a photograph so that no two girls sit next to each other is

6!5!

(5!)2

(5!)10!​

(5!)210!​