Question

The number of unpaired electrons in ferrous ion is:

• A. 5
• B. 4
• C. 3
• D. 2

Answer 1

Answer: (B)

${}_{26}Fe=1s^2,2s^{2}2p^6,3s^{2}3p^{6}3d^6,4s^2$ $F{e}^{2+}=[Ar]3d^6$ Hence, unpaired electrons in $F{e}^{2+}$ (ferrous ion) = 4