The number of turns in the coil of an A.C. generator are 100 and its cross-sectional area is 2.5 m 2. The coil is revolving in a uniform magnetic field of strength 0.3 T with the uniform angular velocity of 60 rad / s. The value of maximum value produced is kV.

Question

The number of turns in the coil of an A.C. generator are 100 and its cross-sectional area is 2.5 m 2. The coil is revolving in a uniform magnetic field of strength 0.3 T with the uniform angular velocity of 60 rad / s. The value of maximum value produced is kV. (A) 1.25 (B) 4.50 (C) 6.75 (D) 2.25

Tardigrade Admin · Accepted Answer

Induced emf e= NBA ω sin ω t for e text max sin ω t=1 So e text max = NBA ω putting values e text max =4.5 × 103 volt e text max =4.5 kV

Q. The number of turns in the coil of an A.C. generator are $100$ and its cross-sectional area is $2.5 m^{2}$ . The coil is revolving in a uniform magnetic field of strength $0.3 T$ with the uniform angular velocity of $60 r a d / s$ . The value of maximum value produced is _____ $kV$ .

$1.25$

$4.50$

$6.75$

$2.25$

Induced emf $e = NB A ω sin ω t$
for $e_{max} sin ω t = 1$
So $e_{max} = NB A ω$
putting values
$e_{max} = 4.5 \times 1 0^{3} v o lt$
$e_{max} = 4.5 kV$

Q. The number of turns in the coil of an A.C. generator are 100 and its cross-sectional area is 2.5m2. The coil is revolving in a uniform magnetic field of strength 0.3T with the uniform angular velocity of 60rad/s. The value of maximum value produced is _____ kV.

1.25

4.50

6.75

2.25