Q.
The number of possible open chain (acyclic) isomeric compounds for molecular formula C5H10 would be
2643
226
Organic Chemistry – Some Basic Principles and Techniques
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Solution:
The total number of acyclic or open chain isomeric compounds for molecular formula C5H10 are as follows:
1. CH2=CH−CH2−CH2−CH3
2. CH3−CH=CH−CH2−CH3 (cis)
3. CH3−CH=CH−CH2−CH3 (trans)
4. CH2=CH−CH(CH3)−CH3
5. CH2=C(CH3)−CH2−CH3
6. CH3−C(CH3)=CH−CH3
Hence, there are total of 6 isomers.