f(x)=∣2x+1∣−3∣x+2∣+∣∣x2+x−2∣∣ =∣2x+1∣−3∣x+2∣+∣x+2∣∣x−1∣ =∣2x+1∣+∣x+2∣(∣x−1∣−3)
Critical points are x=2−1,−2,−1
but x=−2 is making a zero. twice in product so, points of non
differentability are x=2−1 and x=−1 ∴ Number of points of non-differentiability =2